Is Momentum Conserved in a Collision Between Two Unequal Masses?

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In the collision between Ball A and Ball B, the initial momentum is calculated as 1 kg·m/s, derived from Ball A's mass and velocity. After the collision, the final momentum totals 1 kg·m/s, combining the new velocities of both balls. This indicates that momentum is conserved in the system, as the total momentum before and after the collision remains unchanged. The calculations confirm that despite the unequal masses, the principle of conservation of momentum holds true. Therefore, momentum is indeed conserved in this collision scenario.
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Ball A, which weighs 2 kilograms, is moving at 0.5 meters/second and strikes stationary Ball B at the direct center of the ball.
Ball B, which weighs 3 kilograms, moves off at 0.3 meters/second and in the same original direction Ball A was moving. Ball A continues to move forward, but only at 0.1 meters/second. Is momentum conserved? Explain.I don't even know where to start, or what to do so could I have some help with this?
 
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The momentum of the system is conserved if it's the same before the strike and after...
What's the momentum before?
What about after?
 
The system consists of two bodies: ball A and ball B
All the movements are performed along one axis: OX. Let the positive direction coincide with the direction of ball A movement.
Then, the momentum before the strike
P1 = mAvA + mBvB
vA = 0.5 m/s, vB = 0
The momentum after strike
P2 = mAuA + mBuB
uA = 0.1 m/s, uB = 0.3 m/s

So, the conclusion is clear but still up to you)
 

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