Is My Book Correct About the Integral of e^-ax from Negative Infinity to 0?

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Is my book right to write

\int ^{0}_{- \infty}e^{-a|x|}dx = \int ^{0}_{- \infty}e^{ax}dx

?

In case, why?
 
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If x is negative, what is |x|?
 
positive, but -a is still negative.
 
That was not the question. If x is negative, then |x|= -x. For x negative, -a|x|= (-a)(-x)= ax.
 
errmmm...maybe it's best to think of an example...suppose you have x=-2, what is |x|?
 
|-2| = 2
 
leopard said:
|-2| = 2

Right, and if x=-2, what is -x?
 
Should be 2. I can simply put the minus outside the brackets?
 
leopard said:
Should be 2. I can simply put the minus outside the brackets?

Well, if |x|=2 and -x=2, then surely you can say that |x|=-x?:wink:


So...what does that make -a|x|?
 
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