Is My Calculation of the Radius in a Dielectric Strength Problem Correct?

AI Thread Summary
The discussion revolves around calculating the radius of a circular plate in a dielectric strength problem involving a parallel plate capacitor. The dielectric strength and constant of the material are provided, along with the charge stored on the plates. The initial approach used the equation E=Q/(Eo*k*A) to find the area, but clarification was needed on how to derive the radius from the area. The correct method involves rearranging the area formula A = πr² to solve for the radius, leading to the final result of 2.8E-4 m. This confirms that the calculation process is valid, but emphasizes the need to convert area to radius correctly.
kris24tf
Messages
35
Reaction score
0
Dielectric Strength problem. Please Help! :(

If anyone can let me know if I went about this right, I'd appreciate it, as well as any advice.

The dielectric strength of an insulating material is the maximum electric field strength to which the material can be subjected without electrical breakdown occurring. Suppose a parallel plate capacitor is filled with a material whose dielectric constant is 3.5 and whose dielectric strength is 1.4 E 7 N/C. If this capacitor is to store 1.7 E -7 C of charge on each plate without suffering breakdown, what must be the radius of its circular plates?

I started with the equation E=Q/Eo*k*A, then found that A=Q/Eo*k*E.

I then plugged the numbers into this equation to get 2.3E-7/8.85E-12(3.5)(1.4E7).

Is this the right way to do this problem or do I need to do something differently, as I'm not sure if the radius they're looking for could be found with the Area I got?
 
Physics news on Phys.org
The answer should be 2.8E-4 m.To get the radius, you need to use A = πr2. So, rearrange the equation to solve for r and you will get:r = √(A/π)Plug in your value for A and you will get r = 2.8E-4 m.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top