Is My Spring Equation Correct? A Quick Check

  • Thread starter Thread starter asi123
  • Start date Start date
  • Tags Tags
    Spring
AI Thread Summary
The discussion focuses on verifying the correctness of a spring equation related to energy conservation. It emphasizes that gravitational potential energy does not need to be considered initially, as all kinetic energy converts to potential energy in the spring upon impact. Participants agree that the mass will compress the spring until it reaches a maximum displacement, at which point all energy is stored in the spring. The conversation confirms that the initial approach to the problem is correct. Overall, the equation appears to be validated by the participants.
asi123
Messages
254
Reaction score
0

Homework Statement



Ok, I know it's kind of simple but can someone please check if it's correct?

Homework Equations





The Attempt at a Solution

 

Attachments

  • scan0002.jpg
    scan0002.jpg
    34.8 KB · Views: 396
Physics news on Phys.org


There is no need to include gravitational potential in the first part. Once the mass hits the sprig all of the kinetic energy will turn into potential energy stored in the spring.
 


Kurdt said:
There is no need to include gravitational potential in the first part. Once the mass hits the sprig all of the kinetic energy will turn into potential energy stored in the spring.

Yeah, but it goes down a bit forwarder, I mean until it reaches d and then all the energy is in the spring, right?
 


Yes sorry your're right, it all looks fine.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top