Is Newton's 3rd Law Cancelled in This Friction Problem?

  • Thread starter Thread starter Lisciu
  • Start date Start date
  • Tags Tags
    Law
AI Thread Summary
The discussion revolves around a friction problem involving a forklift and crates, challenging the application of Newton's 3rd Law. The original poster initially believes the law is violated due to discrepancies in calculated forces between the forklift and crates. After further analysis, they realize that the book's solution only considers the force for one crate, leading to confusion about action and reaction forces. They clarify their understanding by applying Newton's 2nd Law to derive the number of crates the forklift can push, aligning with their calculations. The conversation highlights the complexities of applying Newton's laws in practical scenarios, particularly regarding action-reaction pairs.
Lisciu
Messages
38
Reaction score
0
Missing template. Moved from technical forums.
Hi Guys,

I was highly studied the Newton's law once again. Probably to recall the concept from the past of my education. Anyway I find out the exercise during solving the friction problems from Hibbeler book.

The exercises is state as :
The fork lift has a weight W1 and center of gravity at G. If the rear wheels are powered, whereas the front wheels are free to roll, determine the maximum number of crates, each of weight W2 that the fork lift can push forward. The coefficient of static friction between the wheels and the ground is μ s and between each crate and the ground is μ 's.

The whole system looks like this:

bCoOXxv.png


And then it's separate on two objects:

FBD of the 1:

JN58EjX.png


FBD of 2:

icY4dKA.png

And there is nothing suprised about that except the action and reaction force from the crates and front wheel.

I expected that those force will be equal like the 3rd Newton law said. But during the solving and after see those images from book solution looks like 3rd Newton law doesn't work anymore...

Could someone explain what is the reason of that? And where is actually the action and reaction force? I'm confused here.
 
Physics news on Phys.org
Lisciu said:
And where is actually the action and reaction force?
The only 3rd law pair here is ##P=-P'##. If you got anything else then you made a mistake.
 
Seriously? :) when you figured it out that I don't know that?

So why P is equal 707,37lb : and P' is equal : 105lb?
 
Lisciu said:
So why P is equal 707,37lb : and P' is equal : 105lb?
That is not correct, but there is no way to tell where you went wrong without more details about how you attempted to solve it.
 
It's okay. I figured it out what is going on here. Because in the solving book author calculated the P' force for just one crate to calculate how many he can push by this fork lift. I realize that if I will calculated it with diffrent approach like typical 3rd law Newton without calculating reaction force for just one crate I will have the same result. I just took the calculate force P from fork lift and then using this force in X direction net force summing (2rd law) get the force of normal acting on. When I have it I just divided it by one crates weight and actually I get the number of crates this system can handle.
 
That's good. I think I probably would have followed something closer to your approach than to the books approach.
 
Yeap, me too. I was just confused for whole day. Then I just sit once again on the problem and realize where was the hatch.

Anyway I will need to create the topic around 3rd Law because I not undestand in 100% this concept specially if someone talk about cancelling force not cancelling force and then i was thinking about this action and reaction force as a unended storry with domino effect in whole body if we consider for example hammer and nail.
 
Back
Top