Is the bracket of graded derivations a natural graded derivation?

  • Thread starter Thread starter MathematicalPhysicist
  • Start date Start date
  • Tags Tags
    Derivation Natural
MathematicalPhysicist
Science Advisor
Gold Member
Messages
4,662
Reaction score
372
I want to prove the next assertion in Jeffrey M. Lee's Manifolds and differential geometry.
If \mathcal{D}_1, \mathcal{D}_2 are (natural) graded derivations of degrees r_1,r_2 respectively, then the operator:
[\mathcal{D}_1,\mathcal{D}_2] := \mathcal{D}_1 \circ \mathcal{D}_2 - (-1)^{r_1 r_2} \mathcal{D}_2 \circ \mathcal{D}_1

is a natural graded derivation of degree r_1+r_2.
I am finding it difficult to prove property 2 and 3 of graded derivation for this bracket.
Property 2 is given in the next page in definition 1.

I am uploading scans of my work (hopefully my hand written work won't stir you away).
 

Attachments

  • Graded1.jpg
    Graded1.jpg
    38.8 KB · Views: 463
  • Graded2.jpg
    Graded2.jpg
    28.2 KB · Views: 473
  • Graded3.jpg
    Graded3.jpg
    24.9 KB · Views: 468
Physics news on Phys.org
this is a homework type question, i.e. not appropriate.
 

Similar threads

Replies
28
Views
6K
4
Replies
175
Views
25K
Replies
9
Views
7K
Replies
42
Views
10K
Replies
38
Views
3K
Replies
56
Views
5K
Back
Top