Is the Calculation of Area Using Riemann Sum Correct?

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I was hoping someone could check my answer?

Use the limit of a Riemann sum to find the area of the region bounded by the graphs of y=2x^3+1, y=0, x=0, x=2.

Area=2
 
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The limit of the Riemann Sum is the integral. So evaluate \int_{0}^{2}2x^3+1dx. I don't get 2. How did you do your problem?
 
A useful formaula is

\int_{a}^{b}f(x) \, dx = \lim_{n\rightarrow\infty} \frac{b-a}{n}\sum_{k=1}^{n}f\left( a+\frac{b-a}{n}k\right)​

hence

\int_{0}^{2}(2x^3+1) \, dx = \lim_{n\rightarrow\infty} \frac{2}{n}\sum_{k=1}^{n}\left[ 2\left( \frac{2k}{n}\right) ^3 +1\right]​
 
Now I am getting two answers-10 for the def integral and 8 for the sum.
 
10 is obviously the correct answer. How are you taking the limit, as n goes to infinity on
\lim_{n\rightarrow\infty} \frac{2}{n}\sum_{k=1}^{n}\left[ 2\left( \frac{2k}{n}\right) ^3 +1\right]
?

Do you know a formula for the sum of k3, k2, and k that you are using?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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