Is the Direct Sum of Two Nonzero Rings Ever an Integral Domain?

kathrynag
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Show that the direct sum of 2 nonzero rings is never an integral domain


I started by thinking about what a direct sum is
(a,b)(c,d)=(ac,bd)
(a,b)+(c,d)=(a+c,b+d)
We have an integral domain if ab=0 implies a=0 or b=0
 
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Hint: The first property is pretty relevant. The second not so much.
 
So we look at (a,b)(c,d) with (a,b) not zero and (c,d) not zero. Then multiplying together will never result in 0
 
What about a=d=1, and b=c=0? Then you get (1,0)*(0,1) = (0,0).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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