Is the Directed Graph for this Circuit Correct?

AI Thread Summary
The discussion focuses on verifying the accuracy of a directed graph drawn for a given circuit. The user questions whether the direction of current I1 in their graph is correct, suspecting it may be opposite to that in the circuit diagram. Analysis indicates that the direction of arrows in a directed graph should match the current flow in the circuit. If discrepancies are found, it may suggest an error in the graph's representation. Ultimately, ensuring the accuracy of the directed graph is crucial for proper circuit analysis.
SpeedBird
Messages
28
Reaction score
0
hello there, I've been given a circuit and I am trying to draw a directed graph for it.
i drew it out in microcap:

www.compsoc.nuigalway.ie/~filter/question.gif[/URL]

im wondering if the graph is correct. i think for some reason the direction of current for I1 in the graph has to be opposite to the direction of the current in the circuit diagram. is this correct? if so, why?

Thanks for your help.

Nik
 
Last edited by a moderator:
Physics news on Phys.org
does anyone have any ideas?
 


Based on the circuit diagram and the directed graph provided, it appears that there may be a mistake in the direction of the current for I1 in the graph. In a directed graph, the direction of the arrows should represent the flow of current in the circuit. However, in the graph provided, the direction of the arrow for I1 is opposite to the direction of the current in the circuit diagram.

To determine if this is correct, you can follow the direction of the current in the circuit diagram and trace it through the directed graph. If the direction of the current in the circuit diagram matches the direction of the arrow in the directed graph, then it is correct. If not, then there may be an error in the direction of the current in the graph.

In this case, it is possible that the direction of the current for I1 in the graph was accidentally reversed. This can happen if the graph was drawn in a hurry or if there was a misinterpretation of the circuit diagram. It is important to double check the direction of the arrows in the directed graph to ensure accuracy.

If the direction of the current in the circuit diagram is opposite to the direction of the arrow in the directed graph, it is important to understand why this is the case. This could be due to the specific configuration of the circuit or the type of components used. It is always a good idea to consult with a teacher or expert in the field to clarify any doubts or confusion.

In conclusion, it is important to carefully check the direction of the arrows in a directed graph for a circuit to ensure accuracy. In this case, it is likely that the direction of the current for I1 in the directed graph needs to be reversed to match the direction of the current in the circuit diagram. It is always better to double check and make sure all components are accurately represented in the graph to avoid any errors or confusion.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top