Is the equation "0 <= x <= 3, 0<= y <= 4, 0 <= z <= 5" for a cuboid?

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The inequalities "0 <= x <= 3, 0 <= y <= 4, 0 <= z <= 5" define the boundaries of a cuboid in three-dimensional space. Each inequality represents a range for one coordinate, creating a volume bounded by six planes. The planes corresponding to these inequalities are x=0, x=3, y=0, y=4, z=0, and z=5. Together, they form the six sides of the cuboid. Thus, the equation indeed represents a cuboid.
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Homework Statement


Sketch the following volume and find the area.


Homework Equations


0 <= x <= 3, 0<= y <= 4, 0 <= z <= 5


The Attempt at a Solution


The notation is confusing me. Is the equation simply representing a cuboid?
 
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If that's all the info you are given, yes.
 
That's not "an equation", it's three different inequalities. The first, 0\le x\le 3 means all points (x, y, z) such that the component, x, is between 0 and 3. That region is bounded by the two planes x= 0 and x= 3.
Similarly 0\le y\le 4 defines a region bounded by the planes y= 0 and y= 4. Finally, 0\le z\le 5 defines the region bounded by the planes z= 0 and z= 5. Those 6 planes form the 6 sides of a rectangular solid or cuboid.
 

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