Is the group of order 175 abelian?

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Homework Statement


Prove that the group of order 175 is abelian.


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The Attempt at a Solution


|G|=175=527. Using the Sylow theorems it can be determined that G has only one Sylow 2-subgroup of order 25 called it H and only one Sylow 7-subgroups called it K. Thus, H and K are normal subgroups of G and G=H x K which is isomorphic to the direct product of H and K. Since |H|=52, then H is Abelian. Since K is of prime order then K is cyclic and therefore also Abelian.

I am not sure whether I can now conclude that G must be abelian since it is the external (or direct) product of abelian subgroups.
 
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Can you try to prove that the direct product of abelian groups is abelian?
 
direct products of abelian groups are abelian, this is obvious. Look at commutators and use the fact that they have trivial intersection.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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