Is the group of order 175 abelian?

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The group of order 175 is proven to be abelian by applying the Sylow theorems. The group |G|=175 can be decomposed into a Sylow 2-subgroup of order 25, denoted as H, and a Sylow 7-subgroup, denoted as K. Both H and K are normal subgroups of G, with H being abelian and K being cyclic, hence abelian as well. The direct product of these abelian groups confirms that G is also abelian.

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Homework Statement


Prove that the group of order 175 is abelian.


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The Attempt at a Solution


|G|=175=527. Using the Sylow theorems it can be determined that G has only one Sylow 2-subgroup of order 25 called it H and only one Sylow 7-subgroups called it K. Thus, H and K are normal subgroups of G and G=H x K which is isomorphic to the direct product of H and K. Since |H|=52, then H is Abelian. Since K is of prime order then K is cyclic and therefore also Abelian.

I am not sure whether I can now conclude that G must be abelian since it is the external (or direct) product of abelian subgroups.
 
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Can you try to prove that the direct product of abelian groups is abelian?
 
direct products of abelian groups are abelian, this is obvious. Look at commutators and use the fact that they have trivial intersection.
 

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