Is the polarization of light relative?

Nirgal
Messages
28
Reaction score
1
I was wondering if anyone had input into this question. Is the measured polarization of a beam of light relative to the frame of the observer?

In the texts on Optics that I've read, there does not seem to be any reference to the observer's frame. It is only mentioned that light is Left-circularly polarized or linearly polarized, etc.

When we describe polarization we ascribe to the light-beam in question a vector representing the polarized state. But is that polarized state the same for each observer?

I am speculating that the polarization is relative and this is my (naive) reasoning.
If we were discussing the path of a bullet, then in the frame of reference of somebody rotating, the path of the bullet would be curved. So the time dependent vector representing the path of the bullet would depend on the frame of reference of the observer.

Now, the physics of light is so bizarre and I can barely understand it that I do not assume that the analogy between bullets and light can be taken very far. The point of the analogy though is that polarization state is described by a vector and similarly the path of the bullet. And since the mathematical abstraction that the vector represents depends on the reference frame for the bullet then I would assume that the polarization similarly depends on the reference frame of the observer as well.

This is one of my problems in physics though. I am constantly in a wrestling match between distinguishing the mathematics from the physics.
 
Physics news on Phys.org
First consider the case of a massive spinning particle. Say that one observer says the particle is spinning like a right-handed screw going into a piece of wood, i.e., clockwise as seen from behind. Another observer who is traveling in the same direction as the particle, but faster, sees the particle as going backward, and therefore says it is spinning like a left-handed screw.

It's different in the case of a massless particle. You can't overtake a massless particle, because massless particles travel at c.

This is also why it's possible to have a law of physics that says that light is always transversely polarized. You can't have a constraint on the polarization of a massive particle, because there would be no way to define the constraint in the frame where the particle was at rest.
 
bcrowell said:
First consider the case of a massive spinning particle. Say that one observer says the particle is spinning like a right-handed screw going into a piece of wood, i.e., clockwise as seen from behind. Another observer who is traveling in the same direction as the particle, but faster, sees the particle as going backward, and therefore says it is spinning like a left-handed screw.

It's different in the case of a massless particle. You can't overtake a massless particle, because massless particles travel at c.

This is also why it's possible to have a law of physics that says that light is always transversely polarized. You can't have a constraint on the polarization of a massive particle, because there would be no way to define the constraint in the frame where the particle was at rest.
I suppose you mean massless.
 
Passionflower said:
I suppose you mean massless.

No, I meant massive.
 
bcrowell said:
No, I meant massive.
Oh I see, you are talking about a constraint, took me a second the realize what you wrote.

Sorry for that.
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Back
Top