Is the S-matrix Consistent with Time Dependent Hamiltonian?

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SUMMARY

The discussion centers on the consistency of the S-matrix with a time-dependent Hamiltonian represented as \(\hat{H}(t) = \hat{H}_0 + \hat{V}(t)\). The user queries the validity of the wave function evolution in the Schrödinger picture, expressed as \(\psi_S(t) = e^{\frac{1}{i\hbar}\hat{H}_0t}\hat{S}(t)\psi_S(0)\), and the corresponding time-dependent density matrix \(\hat{\rho}_t = e^{\frac{1}{i\hbar}\hat{H}_0t}\hat{S}(t)\hat{\rho}_H\hat{S}^{-1}(t)e^{-\frac{1}{i\hbar}\hat{H}_0t}\). The relationship for the expectation value \(\left\langle \hat{A} \right\rangle_t = Tr(\hat{A}_S\hat{\rho}_t)\) is also discussed, confirming its coherence with the S-matrix formalism.

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  • Understanding of time-dependent Hamiltonians in quantum mechanics
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  • Knowledge of the Schrödinger and Heisenberg pictures
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Quantum physicists, researchers in theoretical physics, and students studying advanced quantum mechanics concepts, particularly those focusing on time-dependent systems and the S-matrix formalism.

Petar Mali
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When I have time dependent Hamiltonian

[tex]\hat{H}(t)=\hat{H}_0+\hat{V}(t)[/tex]

Is then this relation correct?


[tex]\psi_S(t)=e^{\frac{1}{i\hbar}\hat{H}_0t}\hat{S}(t)\psi_S(0)[/tex]

where [tex]\hat{S}(t)[/tex] is S-matrix.


[tex]\psi_S(t)[/tex] - wave function in Schrödinger picture
 
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If I want time dependent density matrix is it

[tex]\hat{\rho}_t=e^{\frac{1}{i\hbar}\hat{H}_0t}\hat{S}(t)\hat{\rho}_H\hat{S}^{-1}(t)e^{-\frac{1}{i\hbar}\hat{H}_0t}[/tex]

Is this expression OK?

So I have


[tex]\left\langle \hat{A} \right\rangle_t=Tr(\hat{A}_S\hat{\rho}_t)=\left\langle \hat{S}^{-1}(t)\hat{A}_H(t)\hat{S}(t) \right\rangle_{\hat{\rho}_H}[/tex]

Does it make sense?
 

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