Is the Series Ʃ n^4 / e^(n^2) Convergent?

ichilouch
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Homework Statement


determine whether the Ʃ n4 / en2 is convergent or divergent?


Homework Equations





The Attempt at a Solution


Using Root test:
lim of n4/n / en as n approaches infinity
But lim of n4/n as n approaches infinity = ∞0
So: Let N = lim of n4/n as n approaches infinity
and: ln N = lim of 4ln(n)/n as n approaches infinity = ∞/∞
By Lhopitals rule: ln N = lim 4/n as n approaches infinity = 0
thus ln N = 0 ; 1 = N
Therefore: lim of n4/n / en as n approaches infinity = 1/∞ = 0
thus CONVERGE?

Is this solution Ok?
 
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The notation could be improved (might be the conversion to text here), but the method is fine.
Be careful with the domain of n when you check the limit of n^(4/n): you want the limit for natural numbers, but then you treat n as a real number. This is possible (a limit for real numbers for n->infinity is also a limit for natural numbers), but you have to consider it.
 
I think it's correct. For practice, try using the ratio test using inequalities.
 
Are there another way on how to test the convergence of this series?
 
Yes. Take the ratio test. Then use the definition of Euler's constant

e=\lim_{n\rightarrow \infty}\left(n+\frac{1}{n}\right)^n

to find where the limit lies
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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