Is the Velocity Equation v^2 = v0^2 + 2ax Dimensionally Correct?

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skippinrocks
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Hello physicists!
I'm taking a physics class and I'm in need of some assistance. I'm just starting out, so bear with me. The question I'm confused about is probably quite simple and I'm just not getting it..


q. Show that the equation v^2 = v0^2 + 2ax is dimensionally correct, where v and v0 represent velocities, a is acceleration and x is distance.

a. i said:

v^2 = v0^2 = (L/T)^2
2ax = 2(L/T)^2

Any assistance would be greatly appreciated. Thanks !
 
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Welcome to Physics Forums, Skippinrocks.

It says "show that", so you should probably show a little more detail in the second part:
2ax has dimensions (L/T²)(L) = L²/T² = (L/T)²