Is the Velocity of a Point Constant or Variable?

  • Thread starter Thread starter Jack3145
  • Start date Start date
  • Tags Tags
    Point Velocity
AI Thread Summary
The discussion centers on the equation for the position of a point given its velocity vector. When the velocity vector is constant, the equation x^{b} correctly represents the point's position over time. However, if the velocity vector is variable, as shown in the example with time-dependent components, the equation fails to satisfy the relationship v = dx/dt. This indicates that the velocity of a point can be constant or variable depending on the nature of the velocity vector. Understanding this distinction is crucial for accurately modeling motion in physics.
Jack3145
Messages
14
Reaction score
0

Homework Statement



A point: [x_{0}, y_{0}, z_{0}, t_{0}]
It's velocity: V_{a} = [v_{1}, v_{2}, v_{3}, v_{4}]

What is wrong with this equation:

x^{b} = [x_{0} + v_{1} * t, y_{0} + v_{2} * t, z_{0} + v_{3} * t, t_{0} + t]
 
Physics news on Phys.org
Nothing is wrong with that, as long as V is a constant vector.
For example, if Va = (2, 3, 4, 1) then your formula for x satisfies v = dx/dt.
However, if Va = (3t, t2, 3t - 12, t2/6) it doesn't.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top