Is there a solution to this transcendental equation ?

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    Transcendental equation
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Discussion Overview

The discussion centers around the transcendental equation sinX + cosX = lnX. Participants explore the existence of solutions, methods for finding them, and the nature of the functions involved. The conversation includes both theoretical considerations and numerical approximations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant notes that the equation is not a homework problem and expresses uncertainty about how to start solving it.
  • Another participant suggests that the left-hand side can be expressed as ##\frac12 \sin (2x)##, indicating that any solution must lie within a specific interval.
  • There is a discussion about the correct interpretation of the equation, with some participants clarifying that the operation is addition rather than multiplication.
  • Some participants propose using graphical methods to analyze the functions involved.
  • Several participants mention the uniqueness of the solution and the absence of a closed form for it, suggesting that numerical methods are the best approach.
  • A specific numerical approximation of the solution is provided, indicating it is approximately 1.8893.

Areas of Agreement / Disagreement

Participants generally agree that there is a unique solution to the equation, but there is no consensus on the existence of a closed-form solution. The discussion includes competing interpretations of the equation and its components.

Contextual Notes

Some assumptions about the behavior of the functions sinX, cosX, and lnX are made, but these are not fully explored or resolved. The discussion relies on numerical methods without providing a detailed derivation of the solution.

Monsterboy
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This is not a homework problem, this equation simply occurred to my mind and my math teacher said such an equation either can't exist or he doesn't know the answer.
sinX ➕ cosX = lnX

I don't know how to start...
 
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This looks ugly. To simplify it a bit, notice that the LHS is equal to ##\frac12 \sin (2x)##. In particular, this lies in ##\left[-\frac12,\frac12\right]##, so that any ##x## solving your equation would have to belong to ##\left[\frac1{\sqrt{e}},\sqrt{e}\right]##.

Using some knowledge of the functions ##\sin## and ##\ln## (i.e. knowing where each of them is positive/negative and where each of them is positively/negatively sloped, and using that ##2\in (0,\pi)##), you can use intermediate value theorem to show that the equation has a unique solution ##x^*>0##, and that it satifies ##x^*\in (1, \sqrt{e})##.

As for an explicit solution, good luck.
 
Monsterboy said:
This is not a homework problem, this equation simply occurred to my mind and my math teacher said such an equation either can't exist or he doesn't know the answer.
sinX ➕ cosX = lnX

I don't know how to start...
You could have started by drawing a graph of each function. Note that:

##sin(x) + cos(x) = \sqrt{2}sin(x + \frac{\pi}{4})##

Which simplifies things.
 
economicsnerd said:
This looks ugly. To simplify it a bit, notice that the LHS is equal to ##\frac12 \sin (2x)##.

##sin(x) + cos(x) \ne \frac12 \sin (2x)##

##sin(x)cos(x) = \frac12 \sin (2x)##
 
Was it "+" rather than "*" ?

On my computer, it's showing up as "sin(x) [black square with a white X in it] cos(x)". If it was addition, my bad. Sorry for adding confusion.
 
I think it is some special character, something like a large "+" sign. So it is clearly an addition.
This does not change the result - there is a unique solution, but probably no closed form for it.
 
with intermediate value method X is something like 1.8893...
 
Monsterboy said:
with intermediate value method X is something like 1.8893...

Indeed. Which is the sole numerical solution to sin(x)+cos(x) = ln(x).

It has no closed form, though. Numerical solution is the best you're going to get.
 

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