Is there a solution to this transcendental equation ?

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Monsterboy
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This is not a homework problem, this equation simply occurred to my mind and my math teacher said such an equation either can't exist or he doesn't know the answer.
sinX ➕ cosX = lnX

I don't know how to start...
 
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This looks ugly. To simplify it a bit, notice that the LHS is equal to ##\frac12 \sin (2x)##. In particular, this lies in ##\left[-\frac12,\frac12\right]##, so that any ##x## solving your equation would have to belong to ##\left[\frac1{\sqrt{e}},\sqrt{e}\right]##.

Using some knowledge of the functions ##\sin## and ##\ln## (i.e. knowing where each of them is positive/negative and where each of them is positively/negatively sloped, and using that ##2\in (0,\pi)##), you can use intermediate value theorem to show that the equation has a unique solution ##x^*>0##, and that it satifies ##x^*\in (1, \sqrt{e})##.

As for an explicit solution, good luck.
 
Monsterboy said:
This is not a homework problem, this equation simply occurred to my mind and my math teacher said such an equation either can't exist or he doesn't know the answer.
sinX ➕ cosX = lnX

I don't know how to start...
You could have started by drawing a graph of each function. Note that:

##sin(x) + cos(x) = \sqrt{2}sin(x + \frac{\pi}{4})##

Which simplifies things.
 
Was it "+" rather than "*" ?

On my computer, it's showing up as "sin(x) [black square with a white X in it] cos(x)". If it was addition, my bad. Sorry for adding confusion.
 
I think it is some special character, something like a large "+" sign. So it is clearly an addition.
This does not change the result - there is a unique solution, but probably no closed form for it.
 
with intermediate value method X is something like 1.8893...
 
Monsterboy said:
with intermediate value method X is something like 1.8893...

Indeed. Which is the sole numerical solution to sin(x)+cos(x) = ln(x).

It has no closed form, though. Numerical solution is the best you're going to get.