Is There a Tangent Plane on x^2-3y^2+2z=4 Parallel to 2x+y-z=4?

AI Thread Summary
To determine if there is a point on the surface defined by x^2-3y^2+2z=4 where the tangent plane is parallel to the plane 2x+y-z=4, one must first find the tangent plane at a point (x1,y1,z1) on the surface. The next step involves computing the vector field of normals to the surface and checking if this vector field matches the normal vector of the given plane. If a point exists where these normals are equal, then the tangent plane at that point will be parallel to the specified plane. This approach provides a systematic method to solve the problem. The discussion emphasizes the importance of understanding the relationship between the surface's tangent plane and the given plane's normal vector.
Romperstomper
Is there a point on the surface of x^2-3y^2+2z=4 where the tangent plane is parallel to the plane 2x+y-z=4?

I can find a plane tangent to the surface at a certain point, but I'm lost on this one. Any help will be appretiated.
 
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Find the tangent plane to the surface at a point (x1,y1,z1).

Then see if there's any (x1,y1,z1) such that this plane is parallel to 2x+y-z=4
 
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This might work:
Compute the vector field of normals to your surface.
Check if your vector field is equal at some point to the normal of your plane.
 
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