- #1
alligatorman
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I'm trying to prove that if M,N are normal in G and MN = G, then
[tex]G/(M\cap N)\cong G/M \times G/N[/tex]
In an attempt to use the 1st Isom. Thm, I have a homomorphism from G to G/M x G/N :
[tex]g \mapsto (gM, gN)[/tex]
The kernel is [tex]M\cap N[/tex], so I just have to show that the function is onto to get the isomorphism.
My guess is that (aM, bN) = (abM, abN). I am having a difficult time showing this, or I may be wrong.
Any help?
[tex]G/(M\cap N)\cong G/M \times G/N[/tex]
In an attempt to use the 1st Isom. Thm, I have a homomorphism from G to G/M x G/N :
[tex]g \mapsto (gM, gN)[/tex]
The kernel is [tex]M\cap N[/tex], so I just have to show that the function is onto to get the isomorphism.
My guess is that (aM, bN) = (abM, abN). I am having a difficult time showing this, or I may be wrong.
Any help?
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