Is this a variant of Euler's Formula? Understanding e^iy = cosy + isiny

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SUMMARY

The discussion centers on Euler's formula, specifically the expression e^ikx = cos(kx) + isin(kx), which is a variant of the classic Euler's formula e^ix = cos(x) + isin(x). The transformation involves substituting y with kx, demonstrating that the formula holds for any real number k. This confirms that the variant is indeed a form of Euler's formula, applicable in various mathematical contexts.

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SpartanG345
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Eulers formula says that e^ix = cosx + isinx

but in my textbook there's another formula its e^ikx = coskx + isinkx
i still can't figure out how they got that. Is this still eulers formula? and how do u get it in that form
 
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e^iy = cosy + isiny

Let y = kx

e^ikx = coskx + isinkx
 

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