Is this assumption correct? (dynamic friction)

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A particle of mass M slides towards a wall with a coefficient of dynamic friction μ = 0.4, initially moving at 6 m/s and 1 meter away. The frictional force is calculated as μ times the normal force, resulting in a deceleration of 4 m/s². Using the SUVAT equations, the final velocity upon impact is determined to be approximately 5.29 m/s. The time taken to reach the wall is calculated to be about 0.1775 seconds. The discussion highlights the efficiency of using different SUVAT equations for solving the problem.
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A particle of mass M slides on a horizontal surface with coefficient of (dynamic) friction
μ = 0.4. At time t = 0 it is 1m from a vertical wall, moving at 6 m/s perpendicularly towards it. When does it strike the wall? ( You may assume it is less than 1 second)

Homework Equations



friction = μ x N

where N is the normal force

suvat equations

The Attempt at a Solution



friction = μ x N

M x a = μ x M x g where g = 10 m/s^2

a = 0.4 x g = 4 m/s^2

I want to know if I can take this as a deceleration? Therefore hitting the wall with a velocity of :

v^2 = u^2 + 2as where u = 6 m/s s = 1m a = -4 m/s^2

v = 5.29 m/s

and where the time taken is :

v = u + at

t = 0.1775 seconds
 
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I've not checked your arithmetic, but your method looks fine to me.

One minor point: you have used two SUVAT equations here. However, if you would have used the equation s = ut + 1/2at2, you could have cut your working in half.
 
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