Is this correct (I was just a little worried that I've got a power of 1 that's not equal to 1)?:(adsbygoogle = window.adsbygoogle || []).push({});

1^{ln(5)/2πi}= 5

proof:

using x = π in Euelr's identity:

e^{xi}= cos(x) + isin(x)

e^{πi}= -1

square both sides:

e^{2πi}= 1

putting both sides to the power of ln(5)/2πi

1^{ln(5)/2πi}= (e^{2πi})^{ln(5)/2πi}= e^{ln(5)}= 5

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# Is this correct

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