Is This Heat Transfer Calculation for a Box with Heated Liquid Correct?

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SUMMARY

The heat transfer calculation for a box containing a heated liquid is defined by the equation: delta Qtotal = ([Abox*delta T / (d1/k1+d2/k2)] + [Alid*delta T / (dlid/klid)] + [hair* Aair * delta T]) * delta t. This formula accurately accounts for heat loss through the box's walls and lid, but it is crucial to recognize that air resistance operates in series with the thermal resistances of the box and lid materials. The objective is to determine the necessary lid coverage percentage to achieve a specific cooling rate of the liquid.

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Robbyj
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Say we have a box made of two materials (a box with an internal lining) and a lid for the box made of a certain material. If I fill the box with a heated liquid and cover a certain percentage with the lid, is the following calculation correct for heat loss in the liquid if you ignore any film or scale effects or am I going about this the wrong way?

delta Qtotal = ([Abox*delta T / (d1/k1+d2/k2)] + [Alid*delta T / (dlid/klid)] + [hair* Aair * delta T]) * delta t

The eventual purpose is to calculate the percentage of the box that needs to be covered by the lid in order to allow the liquid to cool to a certain temperature range in a specific amount of time.
 
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No. The air resistance is in series with the resistance of the box wall and the lid, not parallel.
 

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