And for (ii) solve for VIN as a function of R2.CWatters said:I think the best you can do is calculate R2 as a function of Vin for 3b(i) but then you are stuck for (ii).
Its an assignment question which I believe they have messed up on by omitting information.donpacino said:Where did this problem come from?
any chance a Vout value is given on a previous page?
If you had Vout you could get both as a function of Vout
looks good to me!Enochfoul said:Hi
The missing piece has been found Vout= 7.5V
Using the formula: Vout=Vref*(R1+R2/R2)
Vout=1.25(10+2/2) = 7.5
R2 must be 2 does that look right?
The problem stated had missing info. The Vout should have been 7.5V. Sorted it now thanks the lecturer missed it off by accidentrude man said:What happened to part (ii)? We await with bated breaths ...
Yes I know, and part (a) was I presume solved. But what about part (b)? It's still an interesting problem.Enochfoul said:The problem stated had missing info. The Vout should have been 7.5V. Sorted it now thanks the lecturer missed it off by accident
D=Vout/Vin. There are 2 knowns in the question Duty Cycle which is 30% and Vout which is 7.5V. So Vout is 30% of Vin.rude man said:Yes I know, and part (a) was I presume solved. But what about part (b)? It's still an interesting problem.
There seems to be some parens missing: Vout=Vref*(([/color]R1+R2)[/color][/color]/R2)Enochfoul said:Using the formula: Vout=Vref*(R1+R2/R2)
The answer is correct. Good going.Enochfoul said:D=Vout/Vin. There are 2 knowns in the question Duty Cycle which is 30% and Vout which is 7.5V. So Vout is 30% of Vin.