Is This Node Voltage Analysis Correct?

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SUMMARY

The discussion centers on using the node voltage method to determine the voltage at point A with respect to ground in a circuit involving resistors R3 (147 ohms), R4 (68 ohms), and an additional resistor (82 ohms). The user initially set up the current equations correctly but made an error in the sign of the current through R3. The correct formulation requires adjusting the current equation to reflect the proper direction, resulting in a positive term for the voltage across R3. This adjustment is crucial for accurately calculating the voltage at point A (VA).

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  • Understanding of node voltage analysis in electrical circuits
  • Familiarity with Ohm's Law and current-voltage relationships
  • Basic knowledge of circuit components such as resistors
  • Ability to solve simultaneous equations
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  • Practice solving circuits with multiple voltage sources and resistors
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Electrical engineering students, circuit designers, and anyone learning about circuit analysis techniques, particularly those focusing on node voltage methods.

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Homework Statement



In the figure, use the node voltage method to find the voltage at point A with respect to ground.

Sorry for the crudely drawn picture.

Homework Equations



Node voltage analysis

The Attempt at a Solution



First I added R3 and R4. Then I tried to find the current equations.

I have I1 - I2 -I34 = 0

then

(30 - VA)/ 82 - (40 - VA)/ 68 - VA/147 = 0 Now, I don't know if this is right. I've only been working simple circuits without a voltage source in the middle branch.

Can someone verify if I've done this right so far? If I haven't, can you push me in the right direction?

Thanks.
 

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Assume currents flow upwards from batteries.

You have 3 voltages that all equal the voltage Va.

They are:

A: 30 volts minus the voltage across the 82 ohm resistor. I1 * 82

B: 40 volts minus the voltage across the 68 ohm resistor. I2 * 68

C: The total current from the two batteries times the resistance of R3 + R4. (I1 + I2) * 147

So, these voltages are equal to each other.
So, you can say A = B and get an equation involving I1 and I2
and you can say A = C and get another equation involving I1 and I2.

Then solve for these currents and calculate Va.
 
You seem to be in the right direction. From the way you are assuming current directions though, I34 should be (0-Va)/147. This would give you -Va/147, which you end up subtracting so you should get a +Va/147 in your above equation instead of -Va/147.
 

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