Understanding Nuclear Decay: The Role of Beta Emission in 27-Al Disintegration

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27-Al disintegrates to form 29-Al primarily through beta emission, which increases the atomic number. The discussion highlights that beta decay is the correct answer, as it leads to an increase in atomic number without changing the mass number. However, there is confusion regarding the question's validity, as Al-27 is a stable isotope and does not undergo decay. Participants express uncertainty about whether the question is flawed or if it tests fundamental concepts. Ultimately, the consensus indicates that the question is misleading, as Al-27 does not decay under normal conditions.
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Homework Statement


27-Al disintegates to form 29-Al, by what emission this is possible?

a)alpha b)beta c)positron d)proton
answer given- beta

Homework Equations


beta results in atomic no. increase,alpha results in both mass &no. decrease,positron results in decrease in no.,proton results in decrease by 1 in both.


The Attempt at a Solution


the answer i think given is wrong as we want a paricle like neutron to make it happen (which is not in the options)

are answers and options wrong or just my basics are being tested?
 
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This is really late, but for what it's worth, your thinking is correct and the question is wrong (besides, Al-27 is the stable isotope - it does not decay).
 

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