Is This Sum Exponential in 2n?

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The discussion centers on determining whether the sum of binomial coefficients, specifically \(\sum_{x=0}^{n} \binom{2n}{2x}\), is exponential in \(2n\). The poster is exploring the relationship between the number of prime implicants of a boolean function and this sum. They note that excluding certain terms from the binomial coefficients leads to a conjecture that the sum approximates \(2(2n-1)\). The conversation invites insights on relevant combinatorial identities that could clarify this relationship. Overall, the inquiry seeks to understand the exponential nature of the sum in relation to boolean functions.
twoflower
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Hello,

I've been solving a problem which forces me to answer the question: "Is there a boolean function with exponential number (in variable count) of prime implicants of the length n - 1?"

Anyway, during solving this problem I came to this point:

Is the following sum exponential in 2n?

<br /> \sum_{x=0}^{n} \left( \begin{array}{cc} 2n \\ 2x \end{array} \right)<br />

Are there some nice combinatorial identities which I overlooked that can be useful in this case?

Thank you very much.
 
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If you leave out the 2's in the combinatorial symbol, the answer (as you probably know) is 2n. I would guess your sum is something like 2(2n-1), since you are missing about half the terms.
 
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