Is this the answer to this question?

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The discussion centers on a physics problem involving a 22-pound baby on a piston connected to a larger platform. Using the formula F = P × A, the pressure exerted by the baby is calculated to be 1052.65 Pa, allowing for the determination of the weight of the car that can be lifted, which is approximately 977.95 N (99.79 kg). Additionally, it is established that when the baby's piston is fully compressed, the car will be raised by 1 foot, maintaining the volume of liquid constant across both pistons.

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predentalgirl1
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1. (a) If a 22 pound baby sits atop a 1 ft^2 piston that is connected to a 10 ft^2 platform via sealed, water filled pipes, how heavy and massive of a car can the baby's weight lift (answer in pounds, Newtons, and Kilograms)?

(b) If the baby's initial height on the piston is 10 ft, how high will the car be raised after the baby's piston is completely compressed?




2. F=P/A



3. 1 foot = 0.3048 meters
1 ft² = 0.09290304 m²
10ft² = 0.9290304 m²

1 pound = 0.45359237 kilograms
22 pounds = 9.97903214 Kg

a) Pressure = Force / area
Force = Weight of baby = 9.97903214 x 9.8 = 97.79451497 N
Area = 0.09290304
Pressure = 97.79451497 / 0.09290304 = 1052.651398 Pa
Pressure in both piston the same .
1052.651398 = Force / Area
1052.651398 = Weigh of car / 0.9290304
Weight of car = 977.9451497 N
mass = 99.7903214 Kg .

b)
Volume of Liquid is same in both Pistons
V = A x Height
1ft²x10ft = X x 10ft²
X=1 ft .
 
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