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Is this the Wavelength? (Diffraction)

  1. Apr 4, 2012 #1
    I've asked this question about 4 times on yahoo but no one seems to have the brains to answer it!

    Looking at the diagram:

    LA.jpg

    Just trying to get a better understand of "λ = asin Ѳ"

    I've marked what I think is the wavelength...can someone please advise? as I'm trying to get a report done and I don't want to say the wrong thing!

    If that's not the wavelength..is it the green line?

    Thank you!
     
  2. jcsd
  3. Apr 4, 2012 #2
    If pairs are cancelling out then the path difference is 1/2 wavelength.
    I think the green lines are 1/2wavelength so the red+green is 1wavelength
     
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