Is this the Wavelength? (Diffraction)

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SUMMARY

The discussion centers on the equation "λ = asin Ѳ," which relates to the calculation of wavelength in diffraction patterns. The user seeks clarification on identifying the wavelength in a provided diagram, specifically questioning whether the marked wavelength or the green line represents it. The conclusion drawn is that if pairs are canceling out, the path difference corresponds to half the wavelength, indicating that the green lines represent half a wavelength while the combination of the red and green lines represents a full wavelength.

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  • Understanding of basic wave physics concepts, particularly wavelength and diffraction.
  • Familiarity with the sine function and its application in wave equations.
  • Knowledge of path difference in wave interference.
  • Ability to interpret and analyze diagrams related to wave phenomena.
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  • Learn about the mathematical derivation of the wavelength equation "λ = asin Ѳ."
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Students in physics, educators teaching wave mechanics, and anyone involved in optics or sound engineering who seeks to deepen their understanding of diffraction and wavelength calculations.

Modrisco
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I've asked this question about 4 times on yahoo but no one seems to have the brains to answer it!

Looking at the diagram:

LA.jpg


Just trying to get a better understand of "λ = asin Ѳ"

I've marked what I think is the wavelength...can someone please advise? as I'm trying to get a report done and I don't want to say the wrong thing!

If that's not the wavelength..is it the green line?

Thank you!
 
Physics news on Phys.org
If pairs are cancelling out then the path difference is 1/2 wavelength.
I think the green lines are 1/2wavelength so the red+green is 1wavelength
 

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