Is U a Subspace of F([a, b]) for Real-Valued Functions with Certain Conditions?

theRukus
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Homework Statement


Is U = {f E F([a, b]) | f(a) = f(b)} a subspace of F([a, b]), where F([a, b]) is the vector space of real-valued functions de ned on the interval [a, b]? (keep in mind that in the definition of U, the E means belonging to.. I couldn't find an epsilon character)


Homework Equations





The Attempt at a Solution


I know I have to check the following two closure axioms:

Check that C belongs to U where C = A + B and A, B belong to U

Check that C belongs to U where C = kA and A belongs to U and k belongs to real numbers.

My issue is that I just don't know how to portray an example that belongs to U. I hope I'm making some sense here.. I just need to know how A, B should look for my closure axioms.

Thanks
 
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theRukus said:

Homework Statement


Is U = {f E F([a, b]) | f(a) = f(b)} a subspace of F([a, b]), where F([a, b]) is the vector space of real-valued functions de ned on the interval [a, b]? (keep in mind that in the definition of U, the E means belonging to.. I couldn't find an epsilon character)


Homework Equations





The Attempt at a Solution


I know I have to check the following two closure axioms:

Check that C belongs to U where C = A + B and A, B belong to U

Check that C belongs to U where C = kA and A belongs to U and k belongs to real numbers.

My issue is that I just don't know how to portray an example that belongs to U. I hope I'm making some sense here.. I just need to know how A, B should look for my closure axioms.

Thanks
The things in U are functions, so let's assume that f and g belong to U. What does it mean for a function to belong to this set?
 
Well, A(a)=A(b) and B(a)=B(b). Show C(x)=A(x)+B(x) satisfies C(a)=C(b). That's all they're asking for the first closure. That isn't so hard, is it?
 
Not at all! Thanks so much
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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