Is Using Exponent Identities Allowed in Solving Trigonometric Integrals?

XJellieBX
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Homework Statement


Compute \int^{\pi/2}_{0} \frac{sin^{2009}x}{sin^{2009}x + cos^{2009}x}

I used the identity cos^{2}= 1 - sin^{2}, but instead I set the exponent as 2009. And so I ended up with the answer being -1. I'm just wondering whether this is a legal solution or am I not allowed to do that. Thanks.
 
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sin^{2}x + cos^{2}x = 1 is the so called Pythagorean trigonometric identity. It is not valid when replacing the exponent 2 by another number, i.e.,

sin^{n}x + cos^{n}x \neq 1 for n\neq 2.
 
Thank you, I really needed that second opinion =)
 
XJellieBX said:

Homework Statement


Compute \int^{\pi/2}_{0} \frac{sin^{2009}x}{sin^{2009}x + cos^{2009}x}

I used the identity cos^{2}= 1 - sin^{2}, but instead I set the exponent as 2009. And so I ended up with the answer being -1. I'm just wondering whether this is a legal solution or am I not allowed to do that. Thanks.

Try the change of variables x -> pi/2-x to get a new integral. Then add it to the old integral.
 
Thank you =) I found the answer.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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