- #1

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Ψ(x,t)=1/(c-v)t Lets suppose its a function of probability

It depends on time and it affects space.

Is this is a definition of wave function ?

(I know wave function squuared gives probability but I am not asking that )

- Thread starter Quarlep
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- #1

- 257

- 4

Ψ(x,t)=1/(c-v)t Lets suppose its a function of probability

It depends on time and it affects space.

Is this is a definition of wave function ?

(I know wave function squuared gives probability but I am not asking that )

- #2

Nugatory

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In elementary (meaning before the Hilbert space formalism is introduced) quantum mechanics the wave function can be written as a function of position and time, or as a function of momentum and time. You can transform between the two forms; the former is used to calculate the probability of finding the particle at a given position at a given time and the latter to calculate the probability of finding the particle with a given momentum at a given time.

- #3

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##\nabla j(x,t)+\frac{\partial \rho (x,t)}{\partial t}=0##

where:

##j(x,t)=-\frac{i \hbar}{2m}(\psi * \nabla \psi - \psi \nabla \psi*)##

##\rho(x,t)=|\psi|^2##

- #4

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Lets make a problem; The probability of finding particle on the line between zero and t intervals

Line lenght 0 and 2t than whats the probabilty of finding particle between this intervels ?

Can we solve it useing wavefunction

- #5

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- #6

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Can I turn it a wavefunction someway but same logic

- #7

Nugatory

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No. You have to write down the Hamiltonian of the system, then you have to insert that Hamiltonian into Schrodinger's equation and solve for the wavefunction.Can I turn it a wavefunction someway but same logic

- #8

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If I do that ,can I find the right answer ? I want to be sure sorry but thank you