- #1

- 257

- 4

Ψ(x,t)=1/(c-v)t Let's suppose its a function of probability

It depends on time and it affects space.

Is this is a definition of wave function ?

(I know wave function squuared gives probability but I am not asking that )

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- Thread starter Quarlep
- Start date

- #1

- 257

- 4

Ψ(x,t)=1/(c-v)t Let's suppose its a function of probability

It depends on time and it affects space.

Is this is a definition of wave function ?

(I know wave function squuared gives probability but I am not asking that )

- #2

Mentor

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In elementary (meaning before the Hilbert space formalism is introduced) quantum mechanics the wave function can be written as a function of position and time, or as a function of momentum and time. You can transform between the two forms; the former is used to calculate the probability of finding the particle at a given position at a given time and the latter to calculate the probability of finding the particle with a given momentum at a given time.

- #3

- 38

- 3

##\nabla j(x,t)+\frac{\partial \rho (x,t)}{\partial t}=0##

where:

##j(x,t)=-\frac{i \hbar}{2m}(\psi * \nabla \psi - \psi \nabla \psi*)##

##\rho(x,t)=|\psi|^2##

- #4

- 257

- 4

Let's make a problem; The probability of finding particle on the line between zero and t intervals

Line length 0 and 2t than what's the probabilty of finding particle between this intervels ?

Can we solve it useing wavefunction

- #5

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- #6

- 257

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Can I turn it a wavefunction someway but same logic

- #7

Mentor

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Can I turn it a wavefunction someway but same logic

No. You have to write down the Hamiltonian of the system, then you have to insert that Hamiltonian into Schrodinger's equation and solve for the wavefunction.

- #8

- 257

- 4

If I do that ,can I find the right answer ? I want to be sure sorry but thank you

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