How Do You Find the Line of Symmetry for Isosceles Triangle ABC?

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To find the line of symmetry for isosceles triangle ABC, where A is at (4,37) and B and C lie on the line 3y=2x+12, one must first determine the coordinates of points B and C. The line of symmetry for an isosceles triangle is perpendicular to the base BC and passes through the vertex A. To achieve this, the slope of the line BC must be calculated, and then the perpendicular slope can be used to find the equation of the line through point A. The final equation should be expressed in the form px + qy = r.
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ABC is an isosceles triangle such that
AB=AC
A has coordinates (4,37)
B and C lie on the line with equation 3y=2x+12

Find an equation of the line of symmetry of triangle ABC Give your answer in the form px + qy = r where p,q and r
 
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I've requested that this be moved to homework. In any case, before we can help you need to show how much of the problem you can do yourself.
 
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mark123 said:
ABC is an isosceles triangle such that
AB=AC
A has coordinates (4,37)
B and C lie on the line with equation 3y=2x+12

Find an equation of the line of symmetry of triangle ABC Give your answer in the form px + qy = r where p,q and r
Thread moved to the Homework Help forums.

@mark123 -- please show your work on this problem so that we can then provide tutorial help. We are not allowed to help you until you show your work. Thank you.
 
The line of symmetry of an isosceles triangle is always perpendicular to the base. Find the line through (4, 37) and perpendicular to 3y= 2x+ 12.
 

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