Archived Isothermal expansion of gas question

AI Thread Summary
The discussion centers on a homework question regarding the isothermal reversible expansion of an ideal gas between two states with specified pressures. Participants clarify that the entropy change in an isothermal process is not necessarily zero, as it depends on the work done and the system's conditions. The original poster expresses confusion about needing the number of moles for calculations, while others confirm that the problem can be approached with the given information, though the full problem statement is not provided. The conversation emphasizes the importance of understanding entropy as a function of both temperature and pressure. Overall, the participants agree that the problem can be solved with the available data, pending further details.
paulnz
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Hello, I am just wondering if it is possible to actually do the following question based on the information given

Homework Statement


An isothermal reversible expansion, for which pV=constant as shown by the curve

joining State A and State B, takes a system from State A to State B along the curved

line on the diagram above. The pressure of State A is 50 x 10^5 Pa and the pressure of

State B is 12.5 x 10^5 Pa. The system is also taken from State A to State B in two

irreversible steps as indicated by the pathways I and II in the diagram. Each irreversible

step involves expansion against a constant external pressure.



If the system is an ideal gas determine the entropy change for the reversible

expansion from State A to State B, and calculate the increase in the number of

microstates for the system during expansion.




Homework Equations


pV=constant


The Attempt at a Solution



I would have thought you would have required the number of moles of the gas to solve the problem, but I could be wrong? That's what is confusing me. Unless the fact that pV= constant has something to do with it?

attached is the graph as the problem requires.

Thanks for any help.
 

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The entropy change in an isothermal process is zero. @Chestermiller... Is this correct? I got a doubt because the question is long and such a simple answer COULD be wrong.
 
CrazyNinja said:
The entropy change in an isothermal process is zero. @Chestermiller... Is this correct?
No, not in general. Why would you think this?
 
Q=0. There is no energy exchanged. How will the entropy change?
 
CrazyNinja said:
Q=0. There is no energy exchanged. How will the entropy change?
Who says Q=0 for all isothermal processes? What if work is done? Then Q = W.
 
Wait. Did I say Q=0? Forgive me. I meant ΔT=0.
 
CrazyNinja said:
Wait. Did I say Q=0? Forgive me. I meant ΔT=0.
Entropy is not just a function of temperature. It is also a function of pressure (or volume).
 
OK. I guess I have to look up entropy again. By the way, can we do this question using the given information? If yes, then say so, but do not write solution. I will try it out.
 
CrazyNinja said:
OK. I guess I have to look up entropy again. By the way, can we do this question using the given information? If yes, then say so, but do not write solution. I will try it out.
Yes (per mole, unless they tell you the number of moles or the temperature). The OP has not shown the full problem statement, so it not clear whether the temperature was given.
 
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