Prime

Hello my name is Scott Johnson I was just wondering if u could help me with thse two problems im stuck on. I have I deadline for tommorrow so if u could email me back today that would be great.greatlt apprecated

1) a 0.50 cm high object is placed 30 cm in front of a concave mirror that has a 15cm radius of curvature. a)find the position and size of the image and state whether it is real or virtual and upright or inverted. Repeat the distances of b) 15 cm, c) 12 cm, and d) 6 cm. check your calculations with ray diagrams. (20 pts for each letter section)

2)Light at an incident ray of 37degrees enters a flat glass plate (n=1.50). a)what is the angle of refraction inside the glass? b) after the beam leaves the plate, what is the angle between it and the beam incident on the plate? (10 pts for each letter section)

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enigma
Staff Emeritus
Gold Member
Prime,

Forum rules state that for us to help you, you need to show your work and where you got stuck.

It does absolutely nothing for you if someone gives you the answer, and is considered cheating if the problem is graded.

Prime

if u place a .50cm high object in frount of a 30 concave mirrior the curauture of it woul dbe 15 cm in radios

so would this mean that because the distance form the mirroir is cut in half the equals the radious. And would u do that for all of them

most of it makes no sence to me, my teacher gave me this question to see if we were deciated to our work..any sorce made be used in these questions thats why i posted it

Prime

if a .50 cm high object is placed 30 cm in front of a concave mirrior that has 15 cm radious curature.

does this mean that the distance between the mirrior and the object its cut in half to equal the radious?

this is not graded it is just a problem that our teacher has given us to see if were deciated to our work. Any sorces our availbe for uses. Thats why i posted it please help me. Please

Prime
this is the problem i cant understand this

Hello my name is Scott Johnson I was just wondering if u could help me with thse two problems im stuck on. I have I deadline for tommorrow so if u could email me back today that would be great.greatlt apprecated

1) a 0.50 cm high object is placed 30 cm in front of a concave mirror that has a 15cm radius of curvature. a)find the position and size of the image and state whether it is real or virtual and upright or inverted. Repeat the distances of b) 15 cm, c) 12 cm, and d) 6 cm. check your calculations with ray diagrams. (20 pts for each letter section)

2)Light at an incident ray of 37degrees enters a flat glass plate (n=1.50). a)what is the angle of refraction inside the glass? b) after the beam leaves the plate, what is the angle between it and the beam incident on the plate? (10 pts for each letter section)

For question 1a, draw a concave mirror and an object on your graph paper. You should apply the laws of reflection in this case. Light rays from the object parallel to the principle axis will pass through the focus, and vice versa. Repeat the above steps to do part b, c and d. When will the image be real/virtual ?

For question 2, I think you have learnt a formula relating angle of incidence, angle of refraction and refractive index, right? Try to apply that formula.

Last edited:
Prime
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Alexander
Start with 1. recalling thin lens (thin mirror) equation and 2. relationship between radius of curvature and focal length for a mirror.

dav2008
Gold Member
Yeah, this is prolly too late, but some equations to get you started:

f=r/2 where r is the radius of curvature..

and

1/di + 1/do=f
Keeping in mind that the focal distance is negative for diverging instruments and positive for converging ones.

Tom Mattson
Staff Emeritus
Gold Member
Prime,

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