Jogger Vs. The Oak Tree

  • Thread starter StotleD
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  • #1
StotleD
21
0
If a healthy but somewhat direction impaired individual (mass = 81.9 kg) is jogging through the woods and runs straight into a large oak tree at 4.7 m/s. Rebound speed is measured at 4.2 m/s in the opposite direction. If the time of contact with the tree is 46 milliseconds, what is the magnitude of the force that the tree exerts on the jogger?
 

Answers and Replies

  • #2
Pyrrhus
Homework Helper
2,179
1
What have you done? I suggest applying the acceleration definition ([itex] a = \frac{\Delta v}{\Delta t} [/itex]) directly into Newton's 2nd Law.
 
  • #3
KingNothing
869
4
This is a simple application of an impulse. I = Force * time, and is also the change in momentum. Momentum is mass times velocity. Momentum before = 81.9 * 4.7 = 384.93. Momentum after=81.9*-4.2= -343.98. Impulse = 728.91 = force * time. Time=.46. 728.91=force * .46. Force is then equal to 1584.59 newtons.
 

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