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[SOLVED] Just Checking
In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 .
A flea jumps straight up to a maximum height of 0.550m . What is its initial velocity Vsub0 as it leaves the ground?
Express your answer in meters per second to three significant figures.
Since my givens are
x = .550m
[Vsub0] = unknown
[Asubx] = =9.80
Hopefully [Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in
0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)
0 = [Vsub0x]^2 -10.78
10.78 = [Vsub0x]^2
Sqrt(10.78) = 3.28 m/s
I think this is correct but i want to check as the homework system is somewhat unforgiving
Homework Statement
In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 .
A flea jumps straight up to a maximum height of 0.550m . What is its initial velocity Vsub0 as it leaves the ground?
Express your answer in meters per second to three significant figures.
Homework Equations
Since my givens are
x = .550m
[Vsub0] = unknown
[Asubx] = =9.80
Hopefully [Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
The Attempt at a Solution
[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])
Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in
0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)
0 = [Vsub0x]^2 -10.78
10.78 = [Vsub0x]^2
Sqrt(10.78) = 3.28 m/s
I think this is correct but i want to check as the homework system is somewhat unforgiving