Kepler's Third Law and Motion of Two Point Masses

[zxcvbnm]

I'm trying to work through some equations in the paper 'Gravitational Radiation and the Motion of Two Point Masses' (Peters, 1964) but I can't get out the right values

1. Homework Statement
For a binary star system with each mass = 1 solar mass, the equations give the results:
Separation ~ 10 solar radii
Period ~ 4.5 days
Lifetime for decay ~ 3x10¹² years

Homework Equations

T = a⁴/4B
B = (64/5)G³m₁m₂(m₁+m₂)/c⁵

The Attempt at a Solution

Using solar mass = 1.989 x 10³⁰kg,
solar radius = 695700 km
G = 6.67408 x 10^-11 m³kg^-1s^-2
c = 3 x 10⁸ ms^-1

I get B = (1/(3 x 10⁸)⁵)(64/5)(6.67408 x 10^-11)³ x 2 x 1.989 x10³⁰ x 10³ = 6.229 x 10^-42

T = (10 x (695700 x 1000))⁴/4B = ~1.12 x 10⁵¹ s, which isn't at all near 3 x 10¹² years :( Help?

 

[zxcvbnm]

Oh, also regarding Kepler's third law. My lecture notes give it as

(G/4pi²)(m₁ + m₂) t²=a³

where t is orbital period in years, masses are in solar units, and a is in au. This formula also isn't working for me yet?