Kernel and Range of a Linear Mapping

Smazmbazm
Messages
45
Reaction score
0

Homework Statement



Find the kernel and range of the following linear mapping.

b) The mapping T from P^{R} to P^{R}_{2} defined by

T(p(x)) = p(2) + p(1)x + p(0)x^{2}

The Attempt at a Solution



I'm not sure how to go about this one. Normally I would use the formula T(x) = A * v but in this case I don't know how to find A or v. Would be great if someone could point me in the right direction.

Thanks in advanced.
 
Physics news on Phys.org
I assume you know that the kernel is the set mapped to 0. T(p(x))= 0 (for all x) if and only if p(2)= p(1)= p(0)= 0.

And the range is the entire set PR2. Do you see why?
 
Yes I know that the kernel is the set that is mapped to 0. I think I'm just having trouble with understanding what T(p(x)) = p(2) + p(1)x + p(0)x^{2} actual means. It's a bit too general for me. What is p(x)? Is that saying that the power representation for p(x) is p(2) + p(1)x + p(0)x^{2}? Or the mapping of the power series p(x) from P^{R} to P^{R}_{2} results in p(2) + p(1)x + p(0)x{2}

I think I understand why the range is the entire set P^{R}_{2}, because if the kernel only contains the zero vector then the range must contain everything else?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top