Is a 15 A Circuit Breaker Capable of Handling 10.6 A Maximum Current?

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In summary, the circuit breaker is rated for a current of 15 A rms at a voltage of 120 V rms. The largest value of I(max) that the breaker can carry is 10.6A and the average power that can be supplied by this circuit is 1.8kW. The correct calculation for I(max) is 15(rms) * square root of 2. It is important to note that the maximum current cannot be lower than the average current.
  • #1
cseet
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A circuit breaker is rated for a current of 15 A rms at a voltage of 120 V rms. Answer the following questions:
All answers must have three significant digits unless otherwise specified.

1) What is the largest value of I(max) that the breaker can carry? (Unit: A)

answer:

I(max) = 15(rms) / square root of 2
= 10.6A

2) What average power can be supplied by this circuit? (Unit: kW)

P(rms) = I (rms) * V (rms)
= 1.80 kW

pls correct me if I was wrong and pls direct me to the right path...
thanks
cseet
 
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  • #2
Argh, stupid me.

I(max) = 15(rms) / square root of 2 is not correct, it should be:
I(max) = 15(rms) * square root of 2 if I'm not mistaken.
 
Last edited:
  • #3
Hi chen,

what about the 2nd answer? is it correct?

thanks
cseet
 
  • #4
Yes, 1.8kW. By the way, you could have noticed that your first answer is wrong because the maximum current cannot be lower than the average current. :smile:
 
  • #5
Thanks Chen... I see that now...
you have a good day
cseet
 

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