A circuit breaker is rated for a current of 15 A rms at a voltage of 120 V rms. Answer the following questions:(adsbygoogle = window.adsbygoogle || []).push({});

All answers must have three significant digits unless otherwise specified.

1) What is the largest value of I(max) that the breaker can carry? (Unit: A)

answer:

I(max) = 15(rms) / square root of 2

= 10.6A

2) What average power can be supplied by this circuit? (Unit: kW)

P(rms) = I (rms) * V (rms)

= 1.80 kW

pls correct me if I was wrong and pls direct me to the right path...

thanks

cseet

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# Homework Help: Kindly pls check my physics answers

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