Kinematic and Projectile motion equations

AI Thread Summary
To determine the angle of projection where the maximum height equals half the range, the kinematic equations for projectile motion are essential. The range is expressed as R = (Vo^2 sin 2Theta) / g, while the maximum height can be derived from the vertical motion equations. The equation for maximum height is given by (v0 sin θ)² = 2aR, which relates the vertical component of the initial velocity to the range. Participants in the discussion seek clarification on deriving the maximum height formula and its relationship to the range. Understanding these equations is crucial for solving the problem effectively.
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Homework Statement



Find the angle of the projection for which the maximum height is equal half of the range.


Homework Equations



Kinematic and Projectile motion equations
 
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Just use SUVAT equations.
 
I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?
 
LadyMario said:
I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

R(range)= \frac{Vo^2 Sin2\Theta}{g}

For maximum height
(v0Sinθ)2=2aR
 
How did you get that equation for max height?
 
LadyMario said:
How did you get that equation for max height?

(vy)2=(uy)2-2as
 
Thank you so much :)!
 
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