Kinematic Question: Helicopter Height & Mailbag Release Solution | Homework Help

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The height of a helicopter is modeled by the equation h = 2.60t^3, indicating its altitude increases with time. At 2.00 seconds, the helicopter releases a mailbag from a height of 20.8 meters. To determine how long it takes for the mailbag to reach the ground, the quadratic equation is necessary due to the changing velocity influenced by gravity. The initial velocity of the mailbag is 31.2 m/s, but the equation yf = y(initial) + v*delta t is not suitable since the velocity is not constant. The proper approach involves incorporating gravitational acceleration into the calculations.
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Homework Statement



The height of a helicopter above the ground is given by h = 2.60t3 , where h is in meters and t is in seconds. After 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

Homework Equations



yf=y(initial) + v*delta t

The Attempt at a Solution



h = 2.60 (8) = 20.8 (height at the bag is released)
y(initial)=0
v= 7.8t^2= 31.2 m/s
i dun understand if gravity would be used here and if it is can u just use the quadratic eqn
 
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Everything you did looks good. Yes, you'll have to use the quadratic equation.
 
grewas8 said:
yf=y(initial) + v*delta t

this equation isn't right since velocity isn't constant... but you didn't use this equation.
 

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