Kinematics - acceleration in a straight line

[Mitchtwitchita]

A car starts from rest and accelerates at a constant rate in a straight line. In the first second, the car covers a distance of 2.0 m. How fast will the car be moving at the end of the second second?

Xo(1) = 0
X(1) = 2.0 m
Vo(1) = 0
V(1) = 2.0 m/s
t(1) = 1.0 s

Thus, V(1) = Vo(1) + a(1)*t(1)
a(1) = V/t
= (2.0 m/s)/1.0 s
= 2.0 m/s^2

Since constant velocity,

Vo(2) = 2.0 m/s
a(2) = 2.0 m/s^2
t(2) = 1.0 s

V(2) = Vo + at
=2.0 m/s + (2.0m/s^2)(1.0 s)
= 4.0 m/s

Can anybody confirm or refute this please?

 

[Kurdt]

The question says the car covers a distance of two metres, not has a speed of 2m/s.

 

[baba89]

I can confirm that your calculations are correct. The car will be moving at a speed of 4.0 m/s at the end of the second second. This is because the car is accelerating at a constant rate of 2.0 m/s^2, which means its velocity increases by 2.0 m/s every second. Therefore, after two seconds, the car will have a velocity of 4.0 m/s. This is a fundamental concept in kinematics, where acceleration is the rate of change of velocity over time.