- #1

chaspc

- 2

- 0

I've calculated the max height H to be 7.3m but I'm stuck on calculating the time and velocity and all the rest. Can anyone help? Thanks!

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- Thread starter chaspc
- Start date

- #1

chaspc

- 2

- 0

I've calculated the max height H to be 7.3m but I'm stuck on calculating the time and velocity and all the rest. Can anyone help? Thanks!

- #2

jandl

- 18

- 0

You've probably seen equations relating velocity, height, and time. Hint these equations are very common and are even posted in one of the stickies.

Remember that there is a conservation of energy in the system. So the energy of the two individual balls will be equal to the energy of balls when they are stuck together.

- #3

chaspc

- 2

- 0

I know the formulas involved. The problem is the time to collide. With a height of 7.3m, the object drops to the ground in 1.22s. The object fired from the ground comes to a stop in 1.22s also. The collision *should* be when the displacement for both objects is the same - and that should be at the midpoint since the object from the top is accelerating at the same rate the object from the bottom is decelerating. However, I keep getting 1.22 when I expect I should get .61.

- #4

jandl

- 18

- 0

- #5

physixguru

- 335

- 0

The 'y' coordinate becomes equal for both at the time for collision.

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