- #1

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I've calculated the max height H to be 7.3m but I'm stuck on calculating the time and velocity and all the rest. Can anyone help? Thanks!

- Thread starter chaspc
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- #1

- 2

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I've calculated the max height H to be 7.3m but I'm stuck on calculating the time and velocity and all the rest. Can anyone help? Thanks!

- #2

- 18

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You've probably seen equations relating velocity, height, and time. Hint these equations are very common and are even posted in one of the stickies.

Remember that there is a conservation of energy in the system. So the energy of the two individual balls will be equal to the energy of balls when they are stuck together.

- #3

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I know the formulas involved. The problem is the time to collide. With a height of 7.3m, the object drops to the ground in 1.22s. The object fired from the ground comes to a stop in 1.22s also. The collision *should* be when the displacement for both objects is the same - and that should be at the midpoint since the object from the top is accelerating at the same rate the object from the bottom is decelerating. However, I keep getting 1.22 when I expect I should get .61.

- #4

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- #5

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The 'y' coordinate becomes equal for both at the time for collision.

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