Kinematics Equations: Displacement Calculation with a Wheel | Homework Help"

AI Thread Summary
The discussion focuses on a homework problem regarding the calculation of displacement when a student walks along a curved path using a wheel. The key point is that displacement is defined as the straight-line distance from the starting point to the endpoint, which in this case is 50 meters, regardless of the path taken. Participants emphasize that the problem does not require mathematical calculations but rather an understanding of the concept of displacement versus distance. The confusion arises from the student's use of a wheel that measures the distance traveled, which does not affect the actual displacement. Ultimately, the displacement is simply 50 meters, highlighting the importance of grasping the definition of displacement in physics.
DracoMalfoy
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Homework Statement


A straight line is marked in meters in a field. A student begins at the zero position mark and ends at the 50 position mark. However, the student did not walk along the straight line. He uses a wheel that has a circumference of 1m and finds that it turns 100 times as he walks. What is his displacement?

Homework Equations


  • Vf=Vi+a⋅t
  • Δd=Vi(t)+1/2a⋅t
  • Vf^2=Vi^2+2a⋅Δd
  • Δd=1/2(Vf+Vi)t
Vf= Final Velocity,
Vi=Initial Velocity,
a=Acceleration,
t= Time
Δd= Displacement

The Attempt at a Solution


[/B]
I haven't attempted this because I'm not really sure how to approach it.
 
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Here's a start. Can you say what displacement means?
 
Last edited:
DracoMalfoy said:

Homework Statement


A straight line is marked in meters in a field. A student begins at the zero position mark and ends at the 50 position mark. However, the student did not walk along the straight line. He uses a wheel that has a circumference of 1m and finds that it turns 100 times as he walks. What is his displacement?

Homework Equations


  • Vf=Vi+a⋅t
  • Δd=Vi(t)+1/2a⋅t
  • Vf^2=Vi^2+2a⋅Δd
  • Δd=1/2(Vf+Vi)t
Vf= Final Velocity,
Vi=Initial Velocity,
a=Acceleration,
t= Time
Δd= Displacement

The Attempt at a Solution


[/B]
I haven't attempted this because I'm not really sure how to approach it.

Start by ditching all the irrelevant equations that you wrote (some of which are incorrect anyway). Think about the problem before writing anything.
 
Last edited:
Wow. Well... That was a big help..
 
DracoMalfoy said:
Wow. Well... That was a big help..

I may be being cynical, but I’m wondering if that was sarcasm. If so, you didn’t think about what he said. I will be more explicit.

This problem does not require any math. Seriously. None. Zero. It is all about the definition of displacement. They want to be sure you understand what displacement is and they want to help you avoid a common misconception of what it is (by tempting you to get it wrong). So, as the previous two posters suggested, go look up the definition of displacement and see if you get the distinction they are trying to make with this problem.
 
Cutter Ketch said:
I may be being cynical, but I’m wondering if that was sarcasm. If so, you didn’t think about what he said. I will be more explicit.

This problem does not require any math. Seriously. None. Zero. It is all about the definition of displacement. They want to be sure you understand what displacement is and they want to help you avoid a common misconception of what it is (by tempting you to get it wrong). So, as the previous two posters suggested, go look up the definition of displacement and see if you get the distinction they are trying to make with this problem.
Displacement is final velocity minus initial. Initial is 0 and 50 is final? I guess I wasn't thinking that it would be that obvious and somehow overlooked it or forgot. The wheel thing kind of confused me as well.
 
He took a twisty path and his wheel measures 100m. However, the field says he moved 50 yards or something like that. What is his displacement? Hopefully this is clearer.
 
Nothing to do with velocity.

Look up the difference between distance and displacement.
 
DracoMalfoy said:
Displacement is final velocity minus initial.

No. You really need to crack open your book. It should explain the definition both in words and symbols. Here's another hint: think about the etymology of displacement
 

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