Solve Kinematics in 2D: Rocket Clears 11m Wall

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A rocket is launched at 75 m/s at a 60-degree angle, aiming to clear an 11-meter-high wall located 27 meters away. To determine how much the rocket clears the wall, the vertical and horizontal displacements must be calculated using kinematic equations. The initial vertical position and the time of flight to reach the wall are critical for finding the rocket's height at that distance. The final height can be compared to the wall's height to determine the clearance. The calculations focus on relating vertical and horizontal displacements to solve the problem accurately.
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Homework Statement


A rocket is fired at a speed of 75m/s from ground level, at an angle of 60degrees above the horizontal. The rocket is fired toward an 11-m-high wall, which is located 27m away. By how much does the rocket clear the top of the wall?

Homework Equations


final velocity = initial velocity + (acceleration * time)
displacement = (initial velocity * time) + 1/2 * acceleration(gravity) * time(squared)


The Attempt at a Solution


So, I need to find the final position where the rocket will land and the time it takes to do so.
If final velocity = 0 then I think I can go from there. I just don't know if that would be right.
 
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I think you'd need to find how high the rocket is at 27m away. Then if that is bigger than 11m, you would subtract 11 from the value you got.

so you need to find an equation relating vertical displacement (y) and horizontal displacement(x)
 
Got it. Thank you.
 

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