Kinematics in one dimension

  • Thread starter Coney
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Homework Statement


10. In reaching her destination, a backpacker walks with an average velocity of 1.34 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.68 m/s, due west, turns around, and hikes with an average velocity of 0.447 m/s, due east. How far east did she walk?
(Cutnell, John D.. Physics, 8th Edition. John Wiley & Sons, 012009. p. 53).
<vbk:9780470458754#page(53)>

Homework Equations



The Attempt at a Solution


2.68 m/s2 = 6.44 km/tw
.447 m/s2 = De/te
Avg V = (X - X0)/(t - t0)

The answer is 0.81 km, but I can't figure out how to solve this.
 
Last edited:

Answers and Replies

  • #2
To solve this prob we have to use concept of avg velocity and its formula avg velocity =total distance by total time.1st convert all kms into metres and use the equation 1.34=6440-x/2400+x/0.447 where x is distance travelled in east.solve x and you will get x=.81 approx.Now you can head for my question
 
  • #4
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I'm not quite sure what you're saying. Can you break it down a bit more and maybe format better? I can't tell if you are saying 1.34 = [(6440-x)/(2400+x)]/0.447 or 6440 - (x/2400) + (x/0.447) or some other variation
 
  • #5
I M SAYING 1.34=6440-x/[2400+x/0.447]
 

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