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## Homework Statement

A soccer player kicks the ball toward a goal that is 16.8 m in front of him. The ball leaves his foot at a speed of 16.0 m/s and an angle of 28.0 degrees above the ground. Find the speed of the ball when the goalie catches it in front of the net.

## Homework Equations

x = vt

x = Vot+(1/2)at

^{2}

Vf

^{2}=Vo

^{2}+ax

## The Attempt at a Solution

Vx = (cos 28)(16.0) = 14.1 m/s

Vy = (sin 28) (16.0) = 7.5 m/s

__Horizontal__

x = 16.8 m

V = 14.1 m/s

__Vertical__

a = -9.8 m/s

^{2}

Vyo = 0 m/s

(V = 7.5 m/s?)

I'm stuck as to where I should go from there or even if I started out correctly.

If you can assist me, I would be very grateful. Thank you!