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Kinematics Qn

  1. Jul 20, 2010 #1
    A rocket is launched vertically upwards until it uses up its fuel. It then falls back to Earth. Find the time when the rocket uses up its fuel from the graph.

    My answer was 20s. Is it correct?
  2. jcsd
  3. Jul 20, 2010 #2
    [EDIT]This information is wrong, I made a mistake.

    It's rather difficult to make out what your axis are labeled as. and that is the crucial part of this problem.

    It seems that your x-axis is labeled: t/s
    which I would take to mean that axis is time in seconds.
    and I think your y-axis is labeled: v/ms^(-1)
    which I would take to mean that axis is velocity, with units of meters per second.
    Be careful about that in the future because '/' means divide. Or maybe you were using '|' instead to divide the two?

    Either way, if those assumptions are correct, then I think your answer is wrong.

    You probably guessed 20s because that is where it appears to 'turn around' but if I am correct and that is a velocity graph, then it is a bit trickier than that. Because look at the peak again, it is still positive, not zero. So therefore your velocity is still positive meaning it is still going up.
    Last edited: Jul 20, 2010
  4. Jul 20, 2010 #3
    The direction of motion has nothing to do with the net force, which is directly related to the engine or the fuel.
    Though that's not the tricky part, the problem is quite tricky: it may be easy to get the right answer, but it's not easy to get the right reason. The answer of the OP is correct, but I would like to hear an explanation from the OP :smile:
  5. Jul 20, 2010 #4
    Oh yes, I apologize OP I was wrong. For some reason when I was responding I thought it was asking when the rocket turns around instead of when it runs out of fuel.

    disregard my post, listen to hikaru1221.
  6. Jul 20, 2010 #5
    I think the answer is correct. It is 20 second because the rocket will accelerate until it runs out of fuel at this point the rocket reaches his maximum speed and then the gravitational force plays its role in pulling the rocket which means decreasing the speed or decelerating from the maximum.
  7. Jul 20, 2010 #6
    If I change the value 30 (s) to 40, is the answer still 20s?
  8. Jul 20, 2010 #7
    No. and the maximum Velocity won't be 100 m/s.Correct?
  9. Jul 20, 2010 #8
    I mean, just change the graph a bit by changing the value 30 to 40, the other things remains the same.
  10. Jul 20, 2010 #9
    So you mean the maximum speed will be in 20 s ?
  11. Jul 20, 2010 #10
    Yes, the rocket reaches its max speed at t=20s.
  12. Jul 20, 2010 #11
    If the zero Velocity at 40s I don't thinks the maximum speed is at 20s
    why ?
    because at 20s after the fuel runs out, the force of the gravity takes 10s to decelerate the velocity from 100 to 0, so if the gravitational force is constant and the maximum speed is 100 why does the gravity take 20s to decelerate the velocity to 0 ? You get my point ?
  13. Jul 20, 2010 #12
    Now you get a bit of my point. Think about this. Is it true that the moment the rocket reaches maximum speed is the moment it uses up fuel? Is it the right reason?
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